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Let’s assume that the change in the current is,
IB = (200 – 100) * 10-6 Amp.
= 100 * 10-6 Amp.
Now, according to the collector current, the change in the current is,
Ic = (10 – 5) * 10-3 Amp.
= 5 * 10-3 Amp.
Therefore, the current gain is,
= Ic / IB
= 5 * 10-3/ 100 * 10-6
= 5/ 100 * 10-3
= 50
Therefore, the gain in the current is 50 amp.
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